X^2+x-1,554=0

Solution for X^2+x-1,554=0 equation:

X^2+X-1.554=0

a = 1; b = 1; c = -1.554;
Δ = b2-4ac
Δ = 12-4·1·(-1.554)
Δ = 7.216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{7.216}}{2*1}=\frac{-1-\sqrt{7.216}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{7.216}}{2*1}=\frac{-1+\sqrt{7.216}}{2}
$